Water weighs 62.4 pounds per cubic foot. How much does the water in a tank that measures 7 ft × 4 ft × 9 in, weigh?

Answer:1,310 lbExplanation:1) Calculate the volume of the water in the tank.Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ftVolume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.2) Calculate the weight of 21 ft³ of water.Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:62.4 lb / 1 ft³ = x / 21 ft³ Solve for x:x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.