Write the equation of a line perpendicular to 5x – 4y = - 3 that passes through the point (-5,2).The equation of the line is y =

Answer: 5y + 4x = - 10Step-by-step explanation:Two lines are said to be perpendicular if the product of their gradients = -1.If the gradient of the first line is [tex]m_{1}[/tex] and the gradient of the second line is [tex]m_{2}[/tex] , if the lines are perpendicular, them[tex]m_{1}[/tex] x [tex]m_{2}[/tex] = -1 , that is [tex]m_{1}[/tex] = [tex]\frac{-1}{m_{2} }[/tex]The equation of the line given is 5x - 4y = -3 , we need to write this equation in slope - intercept form in order to find the slope.The equation in slope -intercept form is given as :y =mx + c , where m is the slope and c is the y - intercept.Writing the equation in this form , we have5x - 4y = + 34y = 5x -+3y = 5x/4 + 3/4comparing with the equation y = mx + c , then [tex]m_{1}[/tex] = 5/4Which means that [tex]m_{2}[/tex] = -4/5 and the line passes through the point ( -5 , 2 ).Using the equation of line in slope - point form  to find the equation of the line;y - [tex]y_{1}[/tex] = m ( x -  [tex]y_{1}[/tex] )y - 2 = -4/5 ( x +5)5(y - 2 ) = -4 ( x + 5 )5y - 10 = -4x - 205y + 4x = - 10